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-196=(-9.8t^2)
We move all terms to the left:
-196-((-9.8t^2))=0
We calculate terms in parentheses: -((-9.8t^2)), so:We get rid of parentheses
(-9.8t^2)
We get rid of parentheses
-9.8t^2
Back to the equation:
-(-9.8t^2)
9.8t^2-196=0
a = 9.8; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·9.8·(-196)
Δ = 7683.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7683.2}}{2*9.8}=\frac{0-\sqrt{7683.2}}{19.6} =-\frac{\sqrt{}}{19.6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7683.2}}{2*9.8}=\frac{0+\sqrt{7683.2}}{19.6} =\frac{\sqrt{}}{19.6} $
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